function with arguments

Raising a number n to a power p is same as multiplying n by itself p times. Write a function called power that takes a double value for n and an int value for p returns the result as double value. Use a default argument of 2 for p so that if this argument is omitted the number will be squared. Write the main function that gets the values from user the user to test the function.

PROGRAM

#include<iostream.h>

#include<conio.h>

double power(double n,int p=2)

{

double x=1.0; int i;

for (i=0;i<p;i++)

x*=n; return x;

}

void main()

{

double n,res; int p;

char ch; clrscr();

cout<<"Enter a number to be raised to a power: "; cin>>n;

cout<<"Do you want to enter the power (Y/N): "; cin>>ch;

if ((ch=='y')||(ch=='Y'))

{

cout<<"Enter the power to which the number "<<n<<" is to be raised: "; 

cin>>p;

res=power(n,p);

}

else

res=power(n);

cout<<"The result is: "<<res; getch();

}

 

OUTPUT

Enter a number to be raised to a power: 5 Do you want to enter the power (Y/N): Y

Enter the power to which the number 5 is to be raised: 3