C++ program to read the file and output the list in the tabular format

A file contains a list of names and telephone numbers in the following form:

Name             Tel. No.

Write a C++ program to read the file and output the list in the tabular format. The name should be left-justified and numbers right-justified. Use a class object to store each set of data.

#include<iostream.h>

#include<conio.h>

#include<iomanip.h>

#include<fstream.h> class phone

{

public:

char name[20]; long int phone_no; void getdata()

{

cout<<"Enter the name and phone_no"<<"\n"; cin>>name>>phone_no;

}

void putdata()

{

cout<<endl<<setw(20)<<setiosflags(ios::left)<<name<<setw(10) <<setiosflags(ios::right)<<phone_no<<endl;

}

};

void main()

{

fstream f; phone ph; int n;

f.open("phonefile",ios::out|ios::in|ios::app);

clrscr();

cout<<"\nEnter the total no_of records:"; cin>>n;

for(int i=0;i<n;i++)

{

ph.getdata();

f.write((char *)&ph,sizeof(ph));

}

f.seekg(0);

cout<<"\n\nThe content of the file is:\n\n"; cout<<setw(20)<<setiosflags(ios::left)<<"NAME"

<<setw(10)<<setiosflags(ios::right)<<"TELEPHONE_NO"; while(f.read((char *)&ph,sizeof(ph)))

ph.putdata();

f.close();

getch();

}

**********************************OUTPUT********************************

Enter the total no_of records:3 Enter the name and phone_no RAGHU

2456570

Enter the name and phone_no RAJEEV

2457859

Enter the name and phone_no RANJU

2451230

The content of the file is:

NAME                TELEPHONE_NO

RAGHU                  2456570

RAJEEV                2457859

RANJU                   2451230

C++ program that uses a single file

Write a C++ program that uses a single file for both reading and writing the data.

#include<iostream.h>

#include<conio.h>

#include<fstream.h> int main()

{

clrscr();

ofstream outf("ITEM.txt"); cout<<"Enter the filename:"; char name[30];

cin>>name;

outf<<name<<"\n"; cout<<"Enter ITEM cost:"; float cost;

cin>>cost;

outf<<cost;

outf.close();

ifstream inf("ITEM.txt"); inf>>name;

inf>>cost;

cout<<"The name of the item is:"<<name; cout<<"\nItem cost is :"<<cost; inf.close();

getch(); return 0;

}

**************************************OUTPUT****************************

Enter the ITEM name:vicks

Enter ITEM cost:20.3

The name of the item is:vicks

Item cost is :20.299999

Design your own manipulator

Design your own manipulator to provide the following output specification for printing money value:

1)  10 columns width

2)  The character '$' at the beginning

3)  Showing '+' sign.

4)  Two digits precision

5)  Filling of unused spaces with ' * '

6)  Trailing zeros shown

#include<iostream.h>

#include<conio.h>

#include<iomanip.h>

ostream &moneyshow(ostream &output)

{

cout<<'$'; cout.fill('*');

cout.setf(ios::showpos);

cout.setf(ios::showpoint);

cout.width(10);

cout.precision(2); return output;

}

void main()

{

double amount; clrscr();

cout<<"enter the value:"; cin>>amount;

cout<<"\nyour money value:"; cout<<moneyshow<<amount; getch();

}

  

*************************OUTPUT 1***************************************

enter the value:12.2

your money value:$****+12.20

*************************OUTPUT 2***************************************

enter the value:34

your money value:$****+34.00

C++ program to read a list

Write a C++ program to read a list containing item name, item code and cost interactively and display the data in a tabular format as shown below:

NAME  CODE  COST

#include<iostream.h>

#include<conio.h>

#include<iomanip.h> int main()

{

int n,itcode[10]; char item[10][10]; float itcost[10]; clrscr();

cout<<"Enter the no of item:"; cin>>n;

for(int i=0;i<n;i++)

{

cout<<"Enter the item details:"<<i+1; cout<<"\nEnter name:"; cin>>item[i];

cout<”Enter code:"; cin>>itcode[i]; cout<<"Enter cost:"; cin>>itcost[i];

}

cout<<endl<<setw(15)<<"Item name"<<setw(15)<<"item code"<<setw(15)<<"cost"<<endl;

cout<<"\n-------------------------------------	\n";
for(i=0;i<n;i++)
{
cout.fill( ' - ' );
cout.setf(ios::left,ios::adjustfield);

cout.width(15);

cout<<item[i];

cout.setf(ios::left,ios::adjustfield);

cout.width(15);

cout<<itcode[i];

cout.setf(ios::right,ios::adjustfield);

cout<<itcost[i]<<endl;

}

getch();

return 0;

}

***********************************OUTPUT*************************

Enter the no of item:3

Enter the item details:1

Enter name:Rice

Enter code:111

Enter cost:35.4

Enter the item details:2

Enter name:Sugar

Enter code:112

Enter cost:12.3

Enter the item details:3

Enter name:Soap

Enter code:113

Enter cost:60.4

Item name   item code           cost

------------------------------------------------

Rice-----------	111------------	35.400002
Sugar----------	112------------	12.3
Soap-----------	113------------	60.400002

Create a base class called 'SHAPE'

 Create a base class called 'SHAPE' having

-          two data members of type double

-          member function get-data( ) to initialize base class data members

-          pure virtual member function display-area( ) to compute and display the area of

the geometrical object.

Derive two specific classes 'TRIANGLE' and 'RECTANGLE' from the base class. Using these three classes design a program that will accept dimension of a triangle / rectangle interactively and display the area.

#include<iostream.h>

#include<conio.h> class shape

{

protected:double x, y;

public:void getdata(double a, double b)

{

x=a;

y=b;

}

virtual void display_area()=0;

};

class triangle:public shape

{

double triangle_area; void display_area()

{

triangle_area=(1*x*y)/2;

cout<<"area of triangle is:"<<triangle_area<<endl;

}

};

class rectangle:public shape

{

double rectangle_area; void display_area()

{

rectangle_area=x*y;

cout<<"area of rectangle is:"<<rectangle_area;

}

};

int main()

{

clrscr(); shape *p; triangle t; rectangle r;

p=&t; p->getdata(10,30); p->display_area(); p=&r; p->getdata(20,30); p->display_area(); getch();

return 0;

}

*******************************OUTPUT*******************************

area of triangle is:150 area of rectangle is:600

Write a C++ program to illustrate ‘this’ pointer

Write a C++ program to illustrate ‘this’ pointer and pointers to derived classes.

#include<iostream.h>

#include<conio.h> class BC

{

public: int b;

void show()

{

cout<<"b= "<<b<<endl;

}

BC findlarge(BC obj)

{

if(b>obj.b) return *this;

else

return obj;

}

};

class DC:public BC

{

public: int d;

void show()

{

cout<<"b= "<<b<<endl; cout<<"d= "<<d<<endl;

}

};

int main()

{

clrscr(); BC b1,b2; b1.b=10; b2.b=20;

BC Large=b1.findlarge(b2); cout<<"\n Largest is :"; Large.show();

BC *bptr; BC base; bptr=&base; bptr->b=100;

cout<<"Base pointer to base class\n"; bptr->show();

DC derived; bptr=&derived; bptr->b=200;

cout<<"Base pointer to base class\n";

bptr->show(); DC *dptr; dptr=&derived; dptr->d=300;

cout<<"Derived pointer to derived class\n"; dptr->show();

((DC*)bptr)->d=400; cout<<"Type conversion\n"; ((DC*)bptr)->show(); getch();

return 0;

}

**********************OUTPUT********************************

Largest is :b= 20

Base pointer to base class b= 100

Base pointer to base class b= 200

Derived pointer to derived class b= 200

d= 300

Type conversion b= 200

d= 400

Create a 'STRING' class which overloads ‘ = = ' operator

Create a 'STRING' class which overloads ‘ = = ' operator to compare two STRING

objects.

#include<iostream.h>

#include<conio.h>

#include<string.h> class string

{

char *p; int len;

public:

string(){ } string( char *s)

{

len=strlen(s); p=new char[len+1]; strcpy(p,s);

}

friend int operator = =( string &s,string &t);

};

int operator = = ( string &s1,string &s2)

{

if(strcmp(s1.p,s2.p)= =0) return(1);

else return(0);

}

int main()

{

string s1,s2;

char str1[20],str2[20]; clrscr();

cout<<"\nEnter the first string : "; cin>>str1;

cout<<"\nEnter the second string : "; cin>>str2;

s1=str1;

s2=str2; if(s1= =s2)

cout<<"\nStrings are equal"; else

cout<<"\nStrings are not equal"; getch();

return 0;

}

*******************************OUTPUT 1********************************

Enter the first string : cpc

Enter the second string : cs

Strings are not equal

******************************OUTPUT 2**********************************

Enter the first string : CPC

Enter the second string : CPC

Strings are equal